Q:

The length of a rectangle is 2 units more than the width. The area of the rectangle is 24 units. What is the width, in units, of the rectangle?

Accepted Solution

A:
Answer:[tex]2\sqrt{5}[/tex]Step-by-step explanation:So, we know the area is 24, and the length is 2 more than the width. Let's refer to the width as x, and the length as x+2. In a rectangle, area is length times width. So, let's multiply the length and width to get x[tex]x^{2}[/tex] + 4. This is because any number times itself is that number squared. Now that we have that, solve for x. Subtract 4 from both sides of the equation and get x[tex]x^{2} +4.[/tex] Now we have [tex]x^{2} =20[/tex]. What we do next is do the square root of both sides, in order to get x by itself. this gives us the answer of [tex]\sqrt{24}[/tex]. That is the width of the rectangle. If you want to go further, we can simplify the expression. 20 is 4*5, and 4 is a square number. We can rewrite the expression now as x=[tex]\sqrt{4} *\sqrt{5}[/tex]. We know the square root of 4 is 2, but the square root of 5 is too difficult to work with and get an exact answer, so we can leave that as-is. our final answer for the width of the rectangle is [tex]2\sqrt{5}[/tex]. I hope this helps!