Which of the following statements best describes the graph of 3x – 2y = 4? A) it is a straight line joining the points (6, 2), (5, 1), and (7,3).B) lt is a straight line joining the points (0, -2), (2, 1), and (-2, -5).C) It is a curve joining the points (3,-2), (2, 3), and (4. 1).D) lt is a curve joining the points (0, 2), (-2, -1), and (4, 1).

Answer:BStep-by-step explanation:This is actually in the form of ax+by=c which is called standard form for a line.I also know it is linear because the degree is 1.  I know the degree is 1 because both variables are to the first power (you don't see this number because [tex]x^1=x[/tex] or [tex]y^1=y[/tex]).So the choices are between A and B.Let's see if it satisfies A:Checking (6,2) for (x,y):3 x - 2 y=43(6)-2(2)=418  -   4  =4      14    =4 is false so (6,2) is not on the given line.Moving on to B:Checking (0,-2) for (x,y):3 x - 2 y=43(0)-2(-2)=4 0   +  4   =4          4    =4 is true so (0,-2) is on the given line.Checking (2,1) for (x,y):3 x - 2 y=43(2)-2(1)=4 6  -  2  =4       4    =4 is true so (2,1) is on the given line.Checking (-2,-5) for (x,y):3 x - 2 y=43(-2)-2(-5)=4-6   +  10  =4            4  =4 is true so (-2,-5) is on the given line.We have that all three pairs from choice B are contained on the line given.